![]() Other than that, it's just a matter of multiplying each of those steps and adding everything together. Just repeat first, outside, inside, last and you'll remember it. The FOIL method is not too difficult to learn once you remember what it stands for. Multiply the following: \((2x-5)(x-4)\) Solution: Multiply the following: \((6x+1)(2x+9)\) Solution: Here are some more examples of FOIL multiplication: Example: Then distribute the answer onto the remaining binomial. To multiply something complicated like \((4x + 6)(5x - 3)(15 - x)\), just do FOIL on two of the binomials and Now just add everything together to get \(4x^2 + 14x + 12\). Last - multiply the last term in each set of parenthesis: Inside - multiply both of the inside terms: Outside - multiply the two terms on the outside: Here's how to solve \((4x + 6)(x + 2)\):įirst - multiply the first term in each set of parenthesis: Multiply the terms inside the parenthesis in a specific order:įirst, outside, inside, last. That's not too hard to remember if you say it in your head a few If you have something like this: \((4x + 6)(x + 2)\)? That's where This gives you an answer of \(28x + 21\). The distributive property to multiply 7 times 4x and then 7 times 3. = 3x 2 + 2xy + x + 3xy – 12x +(y – 4) (2y + 1)Īgain, apply the foil method on (y – 4) (2y + 1).You already know how to simplify an expression like \(7(4x + 3)\), right? Just use Since the last terms area gain two binomials Sum up the products: Now finish by multiplying the last terms:.Multiply the inner terms of each binomial:.Multiply the outer terms of each binomial:.In this case, the operations are broken down into smaller units, and the results combine:.Sum up the products following the foil order and collect the like terms:.Multiply the last terms of each binomial:.Multiply the outermost terms of each binomial:. ![]() Find the sum of the partial products and collect the like terms:.Multiply the inner terms of the binomial:. ![]() Use the foil method to solve:(-7 x−3) (−2 x+8)
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